The explosion is one of the most iconic actions in movies. Explosions can be used to destroy, to injure, or to scare.
The way an explosion is depicted can vary dramatically. Some use very realistic graphics, while others can be more cartoonish. The intensity and size of the explosions can also differ greatly.
How are explosions depicted in movies? What are some common mistakes that are made when depicting them? How much do you know about them? Read on to find out!
There are two main components of an explosion: the detonation wave and the debris generated by the explosion. The way these components move and interact with each other determine how an explosion looks like and how it affects its surroundings.
This article will discuss some details about how explosions are depicted in movies and how accurate they are. We will start with discussing detonation waves and then move onto debris.
Calculating the magnitude of the momentum before the explosion
Now let’s go back to our original question: What is the magnitude of the momentum of piece A before the explosion?
The answer is very simple: It is zero.
Yes, zero! Piece A does not have any velocity or momentum before the explosion. It does not move or vibrate until the explosion occurs.
This may seem strange, but it is true. Think about it this way: If piece A had any velocity or momentum before the explosion, then it would have to be moving or vibrating in some way. But it’s not! So it has zero velocity and momentum before the explosion.
We can make this more mathematical by defining a new quantity called “kinetic energy.” This is simply the amount of “energy of motion” something has.
Understanding what happens during the explosion
Now let’s look at the explosion itself. What happens during the explosion depends on how much energy is in the explosive and how far away the target is.
If the explosive is close to the target, then most of the energy goes into compressing the target material. If it is far away, then most of the energy goes into accelerating the debris. In either case, some of the energy goes into heat and radiation.
If there is a delay between pressing the button and detonation, then there is time for external forces to act on the explosive device. For example, it can be kicked or shaken before detonation, which would change how it works. It can also be placed in a protective casing that prevents some of its effects on other objects or itself.
Understanding what happens to the momentum after the explosion
Let’s go back to our original question: What is the magnitude of the momentum of piece a before the explosion?
Once the explosion occurs, the piece a has no effect on the total momentum of the system (the rest of the bomb). So, we can say that its total momentum before the explosion is zero.
Since it has no net force acting on it, it will not change its velocity. We can also say that its velocity before the explosion is zero.
Now, let’s think about what happens to its kinetic energy. Since it does not lose any energy due to friction or any other forces, its kinetic energy remains unchanged.
We can also say that since there is no net force acting on piece a, it does not experience any acceleration. Therefore, its speed remains constant following the explosion.
Practical applications of this phenomenon
The discovery of the magnitude of the momentum of a piece of a object before it explodes could have practical applications in the field of engineering.
For example, in the construction industry, this knowledge could be used to assess the stability of structures. Engineers could determine if a structure is stable or unstable by observing the momentum of pieces before they explode.
In more specific cases, such as when there is an earthquake, the ground underneath a structure may shake, causing some pieces to break off. The engineers who are assessing the stability of the structure can now assess whether or not it is stable based on the magnitude of momentum of these pieces before they break off.
This knowledge could also be applied in military situations. In situations where there is explosive warfare, soldiers could use this information to determine whether or not their base is stable or unstable.
Possible extensions |P⃗ A,i|{displaystyle left\lceil \frac {P_{A,i}}{P_{B,i}}}right\rceil >{displaystyle left\lceil \frac {P_{C,i}}{P_{D,i}}}right\rceil >…>{displaystyle left\lceil \frac {P_{N,i}}{P_{O,i}}}right\rceil >>} where P A , i = m a x ( 0 , p − m ) v i 2 + p 2 a 2 {\displaystyle P_{A,i}=max(0,-p-m){v^{2}}+p^{2}a^{2}\;} and P O , i = m a x ( 0 , p − m ) v o 2 + p 2 o 2 {\displaystyle P_{O,j}=max(0,-p-m){v^{2}+p^{2}o^{2}\;} with v i = u r s u r f × t {\displaystyle v^{1}\;{\text{is equal to }}urturf×t{\text{ }}} t = Δ x / v d t {\displaystyle t={\frac {{\Delta x/vdt}}}{vdt}}} d t ≈ Δ x / v d r a w n ∆ y / h τ y l e n g t h ⋅ τ y l e n g t h ⋅ cos φ ∆ z / h τ z l e n g t h ⋅ τ z l e n g t h ⋅ cos φ [ 1 ] | V I |
The extension is possible due to the fact that the magnitude of the momentum before an explosion depends on both the velocity (u surf) and time (t). There are three possibilities:
The surfer has a lower velocity, but a longer time to reach it. The surfer has a higher velocity, but a shorter time to reach it. Both cases above have similar magnitudes of momentum.
Through further research, we will be able to determine how much of an effect each factor has on the magnitude of momentum before an explosion.
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